If one root of the equation x2-2x+k=0 is 1+2i then the value of k is Question If one root of the equation x2-2x+k=0 is 1+2i then the value of k is in progress 0 Math Genesis 2 months 2021-10-05T04:40:43+00:00 2021-10-05T04:40:43+00:00 1 Answer 0 views 0

## Answers ( )

Step-by-step explanation:(1+2i)²-2(1+2i)+k=0

1+4i²+4i-2-4i+k=0

1-4+4i-2-4i+k=0

1-4-2+k=0

-3-2+k=0

-5+k=0

-5=-k

k=5 OK friend